WebAs noted in the comments this function is not defined at $(0,0)$ because we would be dividing by zero. You can however ask whether $\lim_{(x,y)\rightarrow(0,0)}(f(x,y))$ … WebSep 9, 2015 · Tour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site

Solved Find the x-value at which f is discontinuous and - Chegg

WebSep 3, 2024 · Using continuity concepts, the answers are given by:. The function is right-continuous at x = 0.; The function is left-continuous at x = 1.; A function f(x) is continuous at x = a if:. If , the function is left-continuous.; If , the function is right-continuous.; For the given function, the continuity is tested at the points in which the … WebThe asymptote is for g(x) while the function f(x) crosses the asymptote. g(x) approaches the asymptote from the right side but never touches it. In fact, it does not matter whether asymptote is vertical, slant, or horizontal. No function will cross its own asymptote. grandmother sentenced for jan 6

See: Find each x-value at which f is discontinuous and for ... - Brainly

WebSolution : lim x-> x0- f(x) = f(x 0) (Because we have unfilled circle). But, lim x-> x0+ f(x) ≠ f(x 0) (Because we have filled circle at different place). Hence the given function is not continuous at the point x = x 0.. Question 2 : … WebIf you really have $f(0,0)=1$, then it is easy to see that the function is not continuous, because the limit---if it exists---will have to be zero. This can be seen as suggested by … WebWhile for x<0 Lim(x---->0) sin(x)/(-x) By applying limit we get anwer -1 Therefore as left hand limit is not equal to right hand limit so f(x) is discontinuous as f(x) =1 at x=0 Any kind of … chinese hair growth essence