Web10 okt. 2024 · Given: If 31z5 is a multiple of 3 where z is a digit To Find; The value of z so the whole number is divisible by 3 Solution: 31z5 is multiple of '3' divisibility rule of 3 : Sum of digits must be divisible by 3 3 + 1 + z + 5 put z = 0 3 + 1 + 0 + 5 = 9 [9 is multiple of 3] put z = 3 3 + 1 + 3 + 5 = 12 [12 is multiple of 3] put z = 6 WebIf 31z5 is a multiple of 9, where z is a digit, what is the value of z? Answer : We know that a number is a multiple of 9 if the sum of its digits is also divisible by 9. Here, Sum of the digits of 31z5 = 3 + 1 + z + 5 So we have , 3 + 1 + z + 5 = 9k where k is an integer. Checking for different values of k For k = 1:
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Web2 feb. 2024 · Solution: Since 31z5 is a multiple of three, thus the sum of the digits must also be a multiple of 3. Therefore, = 3 + 1 + z + 5 = 9 + z. Thus, 9+z is a multiple of 3 Now, … WebIf 31z5 is a multiple of 3, where z is a digit, what might be the values of z? Solution Since 31z5 is a multiple of 3. Therefore according to the divisibility rule of 3, the sum of all the …
Web26 dec. 2024 · The sum of digits of a number divisible by 3 is a multiple of 33+1+z +5 = 3n⇒ 9+z = 3nWhen n =3,4,5,6 ⇒9+z = 9,12,15,18∴ z = 0,3,6,9. Web11 apr. 2024 · Most important optimization pointers for urn5r15t.szsdbsm.com. This is a prioritized list for urn5r15t.szsdbsm.com of the issues, ordered ascending, and starting with the biggest quick wins for your website.
WebThe multiples of numbers calculator will find 100 multiples of a positive integer. For example, the multiples of 3 are calculated 3x1, 3x2, 3x3, 3x4, 3x5, etc., which equal 3, 6, 9, 12, 15, etc. You can designate a minimum … WebSince 31z5 is a multiple of 3. Therefore according to the divisibility rule of 3, the sum of all the digits should be a multiple of 3. That is, 3+1+z+5 = 9+z Therefore, 9+z is a multiple of 3. This is possible when the value of 9+z is any of the values: 0, 3, 6, 9, 12, 15, and so on. At z = 0, 9+z = 9+0 = 9 At z = 3, 9+z = 9+3 = 12
WebAnswer (1 of 10): We have 3+1+7+5=9+Z 31 z5 is divisible by 3. (9 + z) must be divisible by 3. i.e. (9 + z) = 0 or 3 or 6 or 9 or 15 or 18 since, z is a digit. if 9 + z = 0, then z = - 9 if 9 …
Web4 sep. 2024 · Stack Exchange network consists of 181 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.. Visit Stack Exchange city fish grill allen txWeb1 apr. 2024 · 31 z 5. is divisible by 3. Thus, we will check the divisibility test for 3 that is for the number to be divisible by 3, we have to add all the digits and check if the number is … city fish grill sunday brunchWeb>>If 31z5 is a multiple of 3 , where z is Question 20. If \( 31 = 5 \) is a mult iple of 3 where \( z \) is a digit. what might be the values of \( z \) ? Open in App Solution Verified by Toppr … dictophil ce1WebIf a number is multiple of 3, the the sum of its digits will be multiple of 3. Sum of digits of 31z5 = 3 + 1 + z + 5 = 9 + z 9 + z is a multiple of 3 and since z is a single digit 9 + z is any one of 9, 12, 15 or 18 thus value of z is 0, 3, 6 or 9 respectively. Hence possible value of z is 0,3,6 or 9. Posted by Pankaj Sanodiya Share dicton tempsWeb18 nov. 2015 · I need a program that prints the numbers from 1 to 100. But for numbers that are multiples of three print Multipleof3 instead of the number and for the multiples of five print Multipleof5 p2<-function (x) { x=c (1:100) if (x%%3==0) { print ("Multipleof3") } else if (x%%5 == 0) { print ("Multipleof5") } else { print (x) } } Thank you r dictopro voice activated recorderWebWhile I appreciate the need for conferences and events in cannabis, it’s simply no longer sustainable in its current form. Equity capital has dried up and even… 53 comments on LinkedIn dictons st medardWeb18 mei 2024 · Solution: We know that, according to divisibility rules, if the sum of the digits of a number is divisible by 3, then the given number is a multiple of 3. Since 31z5 is a … city fish market brownsville tn